Probability
(midwest.social)
Math MemesC; the question has two identical answers, it gets removed from the test based on that error
A crocodile has your toddler. It says it will return your child if you can guess its next move. What do you say?
"It's your responsibility now you scaly sucker!" and then voom off on my dune buggy. Also in this scenario I have a dune buggy for reasons.
Distract it while someone sedates/shoots/whatevers it...
Even if you guess the move, it doesn't say it'll be alive or intact, so the safest thing to do is not to play.
"Holy fuck a talking crocodile‽"
Oof. Wrong time to get excited, buddy...
I love this.
Too bad Wrath of Math is probably not on here
Lmao that's fucked up hahaha
It's B - 50%; either correct (50%) or false (50%), binary 0/1, yes/no, score or not.
Diabolical
C, if their is a requirement to show your work and random guesses that don't show work get no credit.
I would answer C) 0% - Ultimately I feel this isn't a "pick the correct answer" type of test and more of a "pick the best answer" type of test.
My reasoning is there are really two questions - one is being answered at random, the other I am answering. The one being answered at random is making any answer it chooses wrong - If it picks A or D (25%), then the correct answer is B (50%). If it picks B (50%), then the answer is either A or D (25%). If it chooses C (0%) then the correct answer is A or D (25%) again. No matter which one is chosen at random, it becomes wrong as soon as it is chosen. So then back to the question on the test that I am answering, the correct answer is C) 0%.
Also, if the teacher marks that wrong, then I am even more correct.
It’s definitely B ) 50%. Ignoring the values for answers, there can only be 1 “correct” answer. If you have 4 options and 1 can be correct, a random guess is 25%. Since there are 2 options for 25%, you have a 50% chance of guessing the correct 25%.
But then the correct answer is b)50%, so the chances or picking that are 25%, my brain hurts now.
You can’t separate the question like that. Whichever answer you circle indicates your assertion that this is the probability of getting the correct answer by uniform random chance.
This means that any answer your circle is wrong, and so the correct answer is to not circle any of them. You could even write e) none of the above to indicate that you have deliberately chosen not to circle one of them instead of skipping the question.
I have had plenty of exams with multiple choice questions that included the possibility of no correct answers, one correct answer, or even multiple correct answers, and we were expected to make that judgement (rather than blindly follow instructions).
hah I see what you did there!
Here's a more fun one:
If you pick an answer to this question at random, what is the chance that you will be correct? Mark at least one of the applicable options.
(a) 20%
(b) 6.25%
(c) 0%
(d) 20%
And as another puzzle, what happens if you swap "at least one of the" for "all"?
Couldn't you argue that 0% is correct?
It's a paradox, no of the answers can be correct, so the chance that you pick the correct one is 0%.
Sure, by picking it, it makes it wrong, but you don't care about that.
If you ran a infite monte carlo test on it, you'd end up with 0% correct answers.
Sure, picking the zero makes it not true again, but you don't care about that - it prooves that the statistical test holds.
The trick is that there is no paradox, only the implication of one. 'If' being the key word - you're not actually being asked to answer randomly, but you are being subtly trolled.
You do not need to pick at all for the paradox to exist. If either A or D is correct, the other is also correct, and the random odds of selecting the correct answer should have been 50%. This is a contradiction. Neither A nor D can be the correct answer.
If B is correct, the random odds of selecting it is only 25% - a contradiction, so B cannot be correct. Likewise, if C is correct, there is a 25% chance of randomly picking C. C is also not correct.
None of the four answers is correct, so there is a 0% chance of randomly picking the correct answer. C is correct, contradiction, C is not correct, C is correct, is not, is too, etc.
The paradox is resolved by knowing the the scantron answer key has A selected. D is not sufficiently identical to A in javascript, so only the students that randomly guessed the correct answer will get credit.
Because the paradox can only be resolved with either A or D as the selected answer, well informed students picking randomly would have a 50% success rate.
If you ignore self-referential nature of the question and stop the iteration at some point, sure, you can argue that any answer is correct.
If you ran a infite monte carlo test on it, you’d end up with 0% correct answers.
That would mean your Monte Carlo test is set up incorrectly because at least 1/4 of the results of the test would be the "correct" answer as per your own argument, thus invalidating it.
Nah it's a paradox. There's no such thing as just a freestanding Monte Carlo test that you can just "run" - you do actually need to define enough parameters to make it tell you anything.
This kind of self-referential stuff feels like a proof of Gödel's incompleteness theorems with extra steps.
self-referential paradox
This. I.e., there is no correct answer.
Sooo, C?
The answer "there is no correct answer" is correct, but the answer isn't 0%. It's a paradox. There isn't a solution, which isn't the same thing as saying there's a 0% chance of getting the right solution (when that is one of the choices).
if c was correct then it would be 25% then 50% and then 25% again ans 50% and 25%
False
The correct answer is to leave all the options unmarked.
If you do pick an answer, then you didn't do it randomly. When not marking the answers, the if-statement has the result of "false", but that's not the question.
If your teacher then asks why you didn't answer it, you can safely and unparadoxically claim that inaction is also an option.
The question is not asking you to pick at random. It's asking you to suppose that you do pick at random and to mark the correct answer not at random.
They aren't asking them to pick an answer at random though.
If "no answer" is in the set of possible answers, then it is not a correct answer because there's then a 20% chance of it being picked at random. But usually that's not the case for tests anyways.
Severe programmer mentality 😂 I like it, but I doubt it would play out in the real world
add a e) 20%
Does anyone else smell pancakes?
Yeah, that's me. They're ready.
Trick question: One of the 25s is an imposter.
It's a mimic-dark souls math. If you pick it, the test eats you.
It's actually 2S with S=12.5
And 50 is 5O, where O=0
Its 25%. The rules of answering a question with a set of options is that you may only choose one and only one is right unless explicitly stated otherwise. Anything else is breaking the rules, which as the taker would be disqualifying. If you start narrowing it down, as in "its 25% and theres two so now i need to guess therefore its 50" you are no longer answering the question at random and you have answered wrong. But you do have to make that coin flip. Good luck.
I've never heard that rule. It sounds like an assumption you're making about the question!
This is the only correct answer to the question as stated.
That of course opens a second can of worms, since now you are actually forced to "pick the answer at random", now with the probability of 50%. But such double entendres are typically not considered for test questions unless explicitly specified.
Yeah, in my opinion the answer is 50%. You got a 50/50 shot at picking the correct 25% answer.
It's gotta be B, right?
If the answer is B, that means there's a 25% chance of getting the right one. So the answer is A and D. But wait... that's 50%
50% means 25%
That means 50%
So it's 0% because it's impossible.
Meaning it's 25%
Damn it
Not really but you're thinking in the right direction!
There is no correct answer because the question and the answers exclude themselves:
For four different options it is 25% but here two options are the same - so you have a 50% chance to land on a 25% - but this means that the correct answer is only in one of the four answers, therefore you're having a 25% chance.
It's a nice demonstration of what happens when the answer and question are intervined and any result changes an aspect of the answer - you're fucked, basically.
well, you are either right or wrong which is 2 options, and 100%/2 is 50%. or something like that
None of the answers are correct, though, because all of the answers are correct as you work through the problem solving for correctness, but once you have actually analyzed the problem for that answer being the answer to the question, it is no longer correct.
I'll do a boring and pointless breakdown of it here:
Statistically, if there are four answers and one of them is correct and it's picked at random, then you have a 25% chance of being correct.
There are two answers that are 25%. If you land on either one of them, that would be correct.
That means that you have a 50% chance of being correct.
There is only one 50% answer, which means you have a 25% chance of being correct.
But there are two 25% answers which means the correct answer is 50%.
But, since none of the answers are correct, then the correct answer is 0%.
But 0% is one of the answers.
So you have a 25% chance of being correct.
I personally would write in "E: None of the above, 20%."
Well wouldn't the correct answer for us to mark be 25% then? As we aren't marking it randomly but we are specifically choosing it, therefore you have a 25% random chance to pick 0% which makes us marking a 25% answer correct
But if 0% was the correct answer, then there would not be a correct answer on the test.
25% != 0%
I suppose that depends on how pedantic you want to be, cause based on how I read it, you need to "solve" the real answer, which is “c) 0%“, due to the paradoxical situation and then figure out what the chance of picking that correct answer is, if you were to randomly chose one of the 4 options, so either of the 25% options should be correct to mark as a chosen answer and not chosen randomly.
But yes, 25% is not equal to 0%, however English is a lovely language
i was doing a bit, shoulda marked it with an /s
sorry you spent valuable time on my bullshit typing that out lol
The right answer is neither a nor b nor c nor d, but "beer with tzatziki".
Mixed?
Aye.
A) 50% B) 50% C) 25% D) 0%
Doesn't make it much easier.
If it's a part of the standardized test that actually does make it much easier. A standardized test only allows to mark one option and that option needs to be derived unambiguously from the question. As such, neither A nor B are actually possible answers under this framework, D is not a possible answer to the question, and we're left with C.
If I was given the original question as part of some standardized test, I would probably think about it for a while, flip a coin mentally, choose either A or D, and then contest it afterwards if it gets marked as being incorrect.
Still too hard. I'll take the 50/50 joker. Which answers remain?
I'd write out '25%' instead of choosing a,b,c or d.
I was thinking otherwise. 4 answers possible would make idd 25% correct.
But since two answers are the same... 3 possible answers. So 33% is solution. That is not an option....
So 0% is the only right answer C
Two answers being the same doesn't mean it's a 1 in 3. It's still 1 in 4 for each option. Basically if you rolled a d4 and chose based on that, you'd have a 50% chance to randomly pick 25, which would make 50% the right answer, but then change the likelihood of being correct 25% again. It's infinitely self referential with no correct answer.
But if 0% is the right answer, then it is an available option. Which could be chosen at random.
No. More like 0 % cause the answer is not here. Like i would ask wich animal has 8 legs. Dog. Cat. Horse. Millipede. No right answer possible. Bad question. Not counting to the total. Maybe i should have said not 0% C but just 0%
Not a 0 % chance you guess right between the 4 choises.
Or not 0% like you say.
To me your way would make it the right answer intentionally. But if you read the other explenations...
There are to much ways to think.
So exept this is a filosofie exam...and you need to explain way you think. And the points are on the reasoning. This is not math than.
This is an error for me. Bad question. So the points from this question chould be taken out of the total.
Probably now all the math knowers are mad at me.
The limit does not exist!
Nobody said it was uniform random, there's probably infinite probability distributions that end up correct
